Solution to Integral Problem

Thanks for ECE IV-2 for bringing this problem to my attention. Feel free to email me if you have any questions with regards to my solution.


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PROBLEM OF THE WEEK 7

Problem of the Week 6 Update

No correct solutions were received.

Problem of the Week 5 Update

Congratulations to Lord Alfred Remorin a 4th year ECE student of PUP Sta. Mesa, this week winner. No other correct solutions were received. See comments for his solution under the Problem of the Week 5.

PROBLEM OF THE WEEK 6

Problem of the Week 4 Update

Congratulations to Lord Alfred Remorin a 4th year ECE student of PUP Sta. Mesa, this week winner. No other correct solutions were received. See comments for his solution under the Problem of the Week 4.

PROBLEM OF THE WEEK 5

Find a quadratic equation with integer coefficients whose roots are cos 72 degrees and cos 144 degrees.

PROBLEM OF THE WEEK 4

Problem of the Week Update 3

Congratulations to this week's winners: Jobert Gimeno - 3rd Year ECE of PUP Sta. Mesa, Cielito Matienzo - 1st Year ECE of PUP Taguig Campus and Lord Alfred Remorin - 4th Year ECE of PUP Sta. Mesa. All the winning solutions gave the following arrangement of answer.

Solution by Jober Gimeno:

PROBLEM OF THE WEEK 3

Problem of the Week 2 Update

Two correct solutions were received. Congratulations to Mr. Isaiah Duazo an ECE student of Rizal Technological University and Mr. Jobert Gimeno an ECE student of PUP Sta. Mesa for submitting the correct solutions.

Solution by Isaiah Duazo:

tan A = 22/7
let A is equal to B + D
tan A = TAn (B + D)
(1) Tan (B + D) = (Tan B + Tan D)/[1 - (TAn B)(Tan D)]

Let the length of the altitude be h:

Tan B = 3/h
TAn D = 17/h

Substituting the value of Tan A, Tan B, and Tan D to Equation 1 and solving for h:

h = 11 units

Area of triangle = (base)(height)/2 = (20)(11)/2 = 110 square units